2349. Design a Number Container System
Design a number container system that can do the following:
Insert **or **Replace a number at the given index in the system.
**Return **the smallest index for the given number in the system.
Implement the NumberContainers class:
NumberContainers()Initializes the number container system.void change(int index, int number)Fills the container atindexwith thenumber. If there is already a number at thatindex, replace it.int find(int number)Returns the smallest index for the givennumber, or-1if there is no index that is filled bynumberin the system.
Example 1:
Input
["NumberContainers", "find", "change", "change", "change", "change", "find", "change", "find"]
[[], [10], [2, 10], [1, 10], [3, 10], [5, 10], [10], [1, 20], [10]]
Output
[null, -1, null, null, null, null, 1, null, 2]
Explanation
NumberContainers nc = new NumberContainers();
nc.find(10); // There is no index that is filled with number 10. Therefore, we return -1.
nc.change(2, 10); // Your container at index 2 will be filled with number 10.
nc.change(1, 10); // Your container at index 1 will be filled with number 10.
nc.change(3, 10); // Your container at index 3 will be filled with number 10.
nc.change(5, 10); // Your container at index 5 will be filled with number 10.
nc.find(10); // Number 10 is at the indices 1, 2, 3, and 5. Since the smallest index that is filled with 10 is 1, we return 1.
nc.change(1, 20); // Your container at index 1 will be filled with number 20. Note that index 1 was filled with 10 and then replaced with 20.
nc.find(10); // Number 10 is at the indices 2, 3, and 5. The smallest index that is filled with 10 is 2. Therefore, we return 2.
Constraints:
1 <= index, number <= 109At most
105calls will be made in total tochangeandfind.
JAVA
class NumberContainers {
private Map<Integer, TreeSet<Integer>> indices = new HashMap<>();
private Map<Integer, Integer> vals = new HashMap<>();
public NumberContainers() {}
public void change(int index, int number) {
if (vals.containsKey(index)) {
int old = vals.get(index);
indices.get(old).remove(index);
if (indices.get(old).isEmpty()) {
indices.remove(old);
}
}
vals.put(index, number);
indices.computeIfAbsent(number, s -> new TreeSet<>()).add(index);
}
public int find(int number) {
if (indices.containsKey(number)) {
return indices.get(number).first();
}
return -1;
}
}
/**
* Your NumberContainers object will be instantiated and called as such:
* NumberContainers obj = new NumberContainers();
* obj.change(index,number);
* int param_2 = obj.find(number);
*/
############
class NumberContainers {
private Map<Integer, Integer> mp = new HashMap<>();
private Map<Integer, TreeSet<Integer>> t = new HashMap<>();
public NumberContainers() {
}
public void change(int index, int number) {
if (mp.containsKey(index)) {
int v = mp.get(index);
t.get(v).remove(index);
if (t.get(v).isEmpty()) {
t.remove(v);
}
}
mp.put(index, number);
t.computeIfAbsent(number, k -> new TreeSet<>()).add(index);
}
public int find(int number) {
return t.containsKey(number) ? t.get(number).first() : -1;
}
}C++
class NumberContainers {
public:
map<int, int> mp;
map<int, set<int>> t;
NumberContainers() {
}
void change(int index, int number) {
auto it = mp.find(index);
if (it != mp.end()) {
t[it->second].erase(index);
it->second = number;
} else
mp[index] = number;
t[number].insert(index);
}
int find(int number) {
auto it = t.find(number);
return it == t.end() || it->second.empty() ? -1 : *it->second.begin();
}
};PYTHON
from collections import defaultdict
import bisect
class NumberContainers:
def __init__(self):
self.index_map = {} # Maps index -> number
self.number_map = defaultdict(list) # Maps number -> sorted list of indices
def change(self, index: int, number: int) -> None:
if index in self.index_map:
old_number = self.index_map[index]
if old_number in self.number_map:
# Remove the old index using binary search
idx_list = self.number_map[old_number]
idx_list.pop(bisect.bisect_left(idx_list, index))
if not idx_list: # Remove empty lists to save space
del self.number_map[old_number]
# Update index mapping
self.index_map[index] = number
# Insert index into sorted list for this number
bisect.insort(self.number_map[number], index)
def find(self, number: int) -> int:
return self.number_map[number][0] if number in self.number_map and self.number_map[number] else -1
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