539. Minimum Time Difference

 C++

  • class Solution {
    public:
        int findMinDifference(vector<string>& timePoints) {
            if (timePoints.size() > 24 * 60)
                return 0;
            vector<int> mins;
            for (auto t : timePoints)
                mins.push_back(stoi(t.substr(0, 2)) * 60 + stoi(t.substr(3)));
            sort(mins.begin(), mins.end());
            mins.push_back(mins[0] + 24 * 60);
            int res = 24 * 60;
            for (int i = 1; i < mins.size(); ++i)
                res = min(res, mins[i] - mins[i - 1]);
            return res;
        }
    };

JAVA

  • class Solution {
        public int findMinDifference(List<String> timePoints) {
            if (timePoints.size() > 24 * 60) {
                return 0;
            }
            List<Integer> mins = new ArrayList<>();
            for (String t : timePoints) {
                String[] time = t.split(":");
                mins.add(Integer.parseInt(time[0]) * 60 + Integer.parseInt(time[1]));
            }
            Collections.sort(mins);
            mins.add(mins.get(0) + 24 * 60);
            int res = 24 * 60;
            for (int i = 1; i < mins.size(); ++i) {
                res = Math.min(res, mins.get(i) - mins.get(i - 1));
            }
            return res;
        }
    }

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